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Тема: Ответить на один экзаменационный вопрос по предмету эконометрика. Учебная работа № 403284 — Заказать, купить, скачать дипломы, рефераты, курсовые, контрольные работы, задачи

Тема: Ответить на один экзаменационный вопрос по предмету эконометрика. Учебная работа № 403284

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Тип работы: Экзаменационный вопрос
Предмет: Экономика
Страниц: 1
Год написания: 2013
Содержание

1. Привести любой практический пример эконометрического уравнения 1Стоимость данной учебной работы: 300 руб.

 

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    Учебная работа № 403284. Тема: Ответить на один экзаменационный вопрос по предмету эконометрика

    Выдержка из подобной работы

    …….

    Блок-схема: Вычитание чисел в форме плавающая точка, сдвиг вправо на один два разряда

    ….. 
    RDYIN==1                да                                                  Преподаватель:
    Иваненко 🙁           

                                                        
    нет                                                                            

                                                                                                                                                                                                            

           ( A1[0…7] ):=( II[4…11] ); B1:=II[0..3] )                  
    m2                              A1[0…7]:=( A1[1..7],B1[0] )  
    m22                                                                                                            

                                                                                                                                   
    B1[0..3]:=(B1[1..3],A1[0])                       

                                                                                                                                                                          
                                                                C=C+1                                              
    m9

                                                                     
    d2                                                                                         
    d15

                                          
     A1[1]==1            
    нет                                                                
    A1[3]==1                                                           

                                                        да                                                                 
    да                                    нет                                 (
    k1,k2) = mod3(A1[0..7]) + mod3(C )                                                                 

                                                                                                                                                                                                  

             ( A2[0…7] ):=( II[4…11] );
    B2:=II[0…3] )                m3                              A1[0…7]:=(
    A1[1..7],B1[0] )   m23                                           

                                                                                                                                 
    B1[0..3]:=(B1[1..3],A1[0])                                                                                                                          

                                                                                
                                                                                                                             

    ( P1,S1[0…4] ) = ( B1[0],B1[0…3] ) — ( B2[0],B2[0…3] );C=A2      
    m4                         

                                                                                                                                                                                                           
    (P2,S2[0…8] )=(A1[0],A1[0…7] ) — (A2[0],A2[0…7] )   m10 Yandex.RTB R-A-98177-2

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    S1[0] +
    S1[1]                                                                                                                                        

                                                             …